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Post by schumi on Jun 12, 2009 15:19:17 GMT
1..S Ulamek..(POL) 2..H Andersen..(DEN) 3..E Sajfutdinov..(RUS) 4..T Gollob..(POL) 5..J Crump..(AUS) 6..F Lindgren..(SWE) 7..C Harris..(GBR) 8..G Walasek..(POL) 9..A Jonsson..(SWE) 10..G Hancock..(USA) 11..[W]..N K Iversen..(DEN) 12..R Holta..(POL) 13..L Adams..(AUS) 14..K Bjerre..(DEN) 15..N Pedersen..(DEN) 16..S Nicholls..(GBR) 17..[R]..P Hougaard..(DEN) 18..[R]..N Klindt..(DEN) speedwaygp.com |
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Post by schumi on Jun 12, 2009 15:19:38 GMT
Which gives us the following heats:
Ht 1..Ulamek..Andersen..Sajfutdinov..Gollob
Ht 2..Crump..Harris..Lindgren..Walasek
Ht 3..Hancock..Iversen..Jonsson..Holta
Ht 4..Pedersen..Bjerre..Nicholls..Adams
Ht 5..Adams..Ulamek..Crump..Jonsson
Ht 6..Bjerre..Hancock..Andersen..Lindgren
Ht 7..Iversen..Pedersen..Harris..Sajfutdinov
Ht 8..Gollob..Walasek..Holta..Nicholls
Ht 9..Lindgren..Nicholls..Ulamek..Iversen
Ht 10..Holta..Crump..Pedersen..Andersen
Ht 11..Walasek..Jonsson..Sajfutdinov..Bjerre
Ht 12..Adams..Gollob..Hancock..Harris
Ht 13..Harris..Holta..Bjerre..Ulamek
Ht 14..Andersen..Adams..Walasek..Iversen
Ht 15..Nicholls..Sajfutdinov..Hancock..Crump
Ht 16..Jonsson..Lindgren..Gollob..Pedersen
Ht 17..Ulamek..Walasek..Pedersen..Hancock
Ht 18..Jonsson..Andersen..Harris..Nicholls
Ht 19..Sajfutdinov..Holta..Adams..Lindgren
Ht 20..Crump..Bjerre..Iversen..Gollob
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Post by Genghis on Jun 12, 2009 16:37:59 GMT
15..N Pedersen..(DEN) 16..S Nicholls..(GBR) Schumi, is that the finishing order?  |
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Post by schumi on Jun 12, 2009 16:48:03 GMT
I very much doubt Scott Nicholls will be finishing second.   |
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Post by Genghis on Jun 12, 2009 17:28:32 GMT
I very much doubt Scott Nicholls will be finishing second. Um.. I didn't quite mean that, but I suspect you know that. |
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